Check numbers with exceptions

Objective

Create a Java program that prompts the user to enter a text (x) and uses a try-catch block to check if the text is a number or not. If it''s a number, display "It''s a number"; otherwise, show "It''s not a number."

It''s important to note that there are more suitable ways to validate user input in Java applications.

Input

Juan

Output

It is not a number

Solution

NumberWithExceptions.java

import java.util.Scanner;

public class NumberWithExceptions {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.print("Enter a text: ");
        String x = input.nextLine();

        try {
            Integer.parseInt(x);
            System.out.println("It is a number");
        } catch (NumberFormatException e) {
            System.out.println("It is not a number");
        }
    }
}

import java.util.Scanner; public class NumberWithExceptions { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a text: "); String x = input.nextLine(); try { Integer.parseInt(x); System.out.println("It is a number"); } catch (NumberFormatException e) { System.out.println("It is not a number"); } } }

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